Answer:
Width 130 ft and
Length 320 ft
Step-by-step explanation:
We are given;
- Length of the rectangular base is 70 ft less than three times the width;
- Perimeter of the rectangular base is 900 ft
We are required to determine the dimensions of the rectangular base;
Assuming the width of the rectangular base is x ft
Then length will be (3x - 70) ft
But;
Perimeter = 2L + 2W
Thus;
900 ft = 2(3x-70) + 2(x)
900 ft = 6x -140 +2x
1040 = 8x
x = 130
Thus;
Width = 130 ft
Length = 3x -70 = 320 ft
Hence the dimensions of the rectangular base are width 130 ft and length 320 ft
Answer:
x=1, y=2
Step-by-step explanation:
x + 7y = 15
x + 2y = 5
Subtract the two equations
x + 7y = 15
-x - 2y =- 5
------------------------
0x +5y = 10
Divide by 5
5y/5 = 10/5
y =2
Now find x
x+2y = 5
x +2(2) = 5
x +4 = 5
Subtract 4 from each side
x-4+4 = 5-4
x = 1
Answer: B
(2x + 6)^2 can be rewrote as (2x + 6)(2x + 6).
Multiply out to get 4x^2 + 24x + 36
