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choli [55]
3 years ago
15

? Question

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
3 0

Answer:

Start on (0,1) and go up two and left three. keep going until you run out of room. then, draw a line through the points.

Step-by-step explanation:

Neporo4naja [7]3 years ago
3 0

Answer:

start on (0,1) and go up two and left three. keep going until you run out of room. then, draw a line through the points.

Step-by-step explanation:

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1) 51.12

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Step-by-step explanation:

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The length of a rectangle is three times its width. The perimeter of the rectangle is 100 inches. What are the dimensions of the
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Answer:

We have l = 2w and 2l + 2w = 100 inches;

Then 4w + 2w = 100 inches;

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Step-by-step explanation:


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Suppose 123 people voted for Danny. If 55 of the votes were from girls what would be the ratio of voted from girls to votes from
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4 years ago
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In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
4 years ago
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