Brian spends 2/5 of his wages on rent and 1/2 on food. If he makes £370 per week, how much money does he have left?

Mathematics

1 answer:

Luden [163]2 years ago

3 0

It is 18.5 because half of 370 is 185 and 2/5 of that is 18.5

You might be interested in

Suppose you have $10,000 to invest. Which of the two rates would yield the larger amount in 4 years. 7% compounded quarterly or

GalinKa [24]

$K=\$10,000\ \ \ and\ \ \ Sum=K\cdot(1+ \frac{p}{100})^n\\----------------------- \\1)\ \ \ 7\%\ quarterly\\\\ \ \Rightarrow\ \ \frac{1}{4} \cdot7\% =1.75\%\ \ annually\ \ \Rightarrow\ \ p=1.75\\\\ quarterly\ \Rightarrow\ \ 4\ times\ annually\ \Rightarrow\ \ 16\ times\ in\ 4\ years\ \Rightarrow\ \ n=16\\\\Sum(7\%)=\$10,000\cdot(1+ \frac{1.75}{100})^{16}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,0175)^{16}\approx\$13199.29\\------------------------\\$

$2)\ \ \ 6.94\%\ daily\\\\ \ \Rightarrow\ \ \frac{1}{365} \cdot6.94\% \approx0.019\%\ \ annually\ \ \Rightarrow\ \ p=0.019\\\\ daily\ \Rightarrow\ 365\ times\ annually\ \Rightarrow\ 1420\ times\ in\ 4\ years\ \Rightarrow\ n=1420\\\\Sum(6.94\%)=\$10,000\cdot(1+ \frac{0.019}{100})^{1420}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,00019)^{1420}\approx\$13096.69\\---------------------------\\\$13,199.29 > \$13,096.69\\\\Ans.\ the\ larger\ amount\ gives\ the\ compounded\ quarterly.$

5 0

3 years ago

Find the value of c so that the polynomial p(×) is divisible by (x-4). p(×)=cx^3-15x-68

Dvinal [7]

Answer:

Step-by-step explanation:

x-4=0

x=4

p(x)=cx^3-15x-68=0

p(x)=c(4)^3-15(4)-68=0

p(x)=64c-60+68=0

p(x)=64c+8=0

p(x)=64c=-8

p(x)=c=-8/64

p(x)=c=-1/8

7 0

2 years ago

If MN = 3 and MN = AB, then AB = 3. This is an illustration of which property?

vova2212 [387]

If MN = 3 and MN = AB, then AB = 3
answer
Transitive Property

8 0

2 years ago

A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

Answer:

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)