Answer:
x = 0 and y = 1 Solution: (0, 1)
Step-by-step explanation:
13x + y = 1 multiply by -6 ⇔ -78x - 6y = -6
2x + 6y = 6 do not change ⇔ +<u> 2x + 6y = 6 </u>
-76x = 0
x = 0
Use the second equation to solve for y if x = 0
2x + 6y = 6
2(0) + 6y = 6
0 + 6y = 6
6y = 6
y = 1 Solution (0,1)
Answer:
Logic with the use of Truth Table
Step-by-step explanation: a) Oleg is a math major= P; Oleg is a economic major=Q; Oleg is required to take math 362=R; Oleg is not required to take 362=←R
b)i) Oleg is a math major or Oleg is an economic major:
P║ Q ║ P∨Q
T T T
T F T
F T T
F F F
ii) Oleg is a math major, then Oleg is required to take Math 362:
P║ R ║ P∧ R
T T T
T F F
F T F
F F F
iii) Oleg is an economic major or Oleg is not required to take Math 362:
Q║ ←R ║ Q ∨ ←R
T T T
T F T
F T T
F F F
c) It is valid because Oleg can only take Math 362 since Oleg is a math major, therefore, it follows that, R ∧ ( P ∨ Q) is valid.
Answer:
- see the attached for the sums
- the magic number (sums of rows, columns, diagonals) is -6
Step-by-step explanation:
The directions tell you what to do and give an example. That work is to be repeated 15 more times. The work is tedious, at best. I found it slightly less tedious to enter the 64 numbers into a spreadsheet and let it do the sums. See the attached for the result.
At the bottom of the array are the sums of columns. At the right are the sums of rows. The upper right and lower left numbers are the sums of the corresponding diagonals.
The "pattern" is that the sums are all -6, which is what you expect from a magic square.
2 * 6^(n-1)
a(sub4) = 2 * 6^(4-1)
a(sub4) = 2 * 6^3
a(sub4) = 2 * 216
a(sub4) = 432
