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2 years ago

What is the solution to the inequality 7x + 2 < -3x + 1?

Mathematics

1 answer:

anastassius [24]2 years ago

5 0

Answer:

$\Large\boxed{\sf{x < -\dfrac{1}{10} }}$

Step-by-step explanation:

In order to find the solutions, you must isolate the inequality on one side of the equation.

7x+2<-3x+1

First, you subtract by 2 from both sides.

7x+2-2<-3x+1-2

Solve.

Subtract the numbers from left to right.

7x<-3x-1

Add by 3x from both sides.

7x+3x<-3x-1+3x

Solve.

7x+3x=10x

10x<-1

Then, you divide by 10 from both sides.

10x/10<-1/10

Solve.

Divide these numbers goes from left to right.

$\Longrightarrow: \boxed{\sf{x < -\dfrac{1}{10} }}$

Therefore, the final answer is x<-1/10.

I hope this helps, let me know if you have any questions.

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Answer:

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Step-by-step explanation:

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3 years ago

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If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

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Answer:

(a) $N(t)=Noe^{kt}$

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$N(t)=Noe^{kt}$

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Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

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Answer:

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If you find it is helpful plz give Brainliest

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