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andrew-mc [135]
3 years ago
13

What is the mass of cerrusite would contain 35g of lead?​

Chemistry
1 answer:
slava [35]3 years ago
7 0

Answer:

i believe its 42

Explanation:

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1.93•100^18 shshshshshshs
AlekseyPX

1930000000000000000

1.93x100x10^16

5 0
3 years ago
At physiological ph, the ionized state of the amino (nh2) group in the r group of lysine is:
kherson [118]

Physiological pH is between 7.37 and 7.43

Lysine is a basic amino acid, which means it has two NH2 groups and one COOH group.

Lysine pKas are: 2.16, 9.06 and 10.05

At low pH (lower than the first pKa, in this case: lower than 2.16) the three groups are protoned. As you increase pH, the first group to lose its proton is the acid group, then the alpha-amino group and then the R-amino group. You will have everything non protoned at a high pH (higher than the highest pKa, in this case: 10.05).

Physiological pH is higher than the lowest pKa and lower than the middle pKa, so it’s the second case: the acid is not protoned, the R-amino is protoned and the alpha amino is protoned.

Protoned aminos are cations: NH3+.

8 0
3 years ago
What is the mass of 13 gold atoms?
Ludmilka [50]

Answer:

uuuh 4.25191 × 10-21 grams????

Explanation:

8 0
3 years ago
if 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?
GrogVix [38]

Here is the full question:

Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

1.000 g copper wire is reacted with 10 mL of concentrated nitric acid (16M). If 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?

Answer:

95.30 %

Explanation:

equation for the reaction is given as:

Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

1.00 g of Cu = \frac{1.00}{63.54 mol of Cu}

= 0.01574 mol of Cu

10 mL of 16 M HNO3 = 10*\frac{16}{1000 mole of HNO3}

= 0.16 mol of HNO3

However, from both variables; we can arrive at a conclusion that Cu is the limiting reagent.

therefore % yield = = 4.70 %

Percentage yield = \frac{actual yield}{theorectical yield} *100%

Percentage yield = \frac{0.953}{ 1.000}* 100%

Percentage yield = 0.953 × 100%

Percentage yield = 95.30 %

3 0
3 years ago
What is the percent hydrogen in ammonium sulfide
sertanlavr [38]
There is no hydrogen in ammonium sulfide it is just 1 ammonium and 1 sulfer
8 0
3 years ago
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