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Neporo4naja [7]
3 years ago
5

Please help !! Science !!

Chemistry
1 answer:
hram777 [196]3 years ago
7 0

Answer: PUMPKIN

Explanation:

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Given that 10.00mL of 0.1894M CH3COOH was titrated with 0.2006M NaOH in this experiment, calculate the volume, in mL, of NaOH re
sertanlavr [38]

Answer:

V_{base}=9.442mL

Explanation:

Hello!

In this case, when acetic acid is titrated with sodium hydroxide, the following chemical reaction is carried out:

CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O

Whereas there is a 1:1 mole ratio between the acid and the base, which means that at the equivalence point we evidence:

n_{acid}=n_{base}

Which in terms of volumes and concentrations is written as:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, solving for the required volume of base, we obtain:

V_{base}=\frac{M_{acid}V_{acid}}{M_{base}}=\frac{0.1894M*10.00mL}{0.2006M}\\\\ V_{base}=9.442mL

Best regards!

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3 years ago
Chemistry please help
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