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3 years ago

Find the area of the sector of the circle Radius. 7kmCentral angle. 2pi over 3 Show steps

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

9514 1404 393

Answer:

51.3 km²

Step-by-step explanation:

The area formula is ...

A = 1/2r²θ . . . . where θ is the central angle in radians

A = 1/2(7 km)²(2π/3) = 49π/3 km² ≈ 51.3 km²

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F(x) = 9 + 4x f(0) = f(-1) = Find the value of x for which f(x) =6 x=

puteri [66]

Answer: x=-3/4

Step-by-step explanation:

Since we know f(x)=6, we can set it equal to the equation.

6=9+4x [subtract 9 on both sides]

-3=4x [divide both sides by 4]

x=-3/4

8 0

4 years ago

You are dealt two cards successfuly without replacement from a shuffled deck of 52 playing card. Find the probability that first

katen-ka-za [31]

The simplified expression is $(\frac{4}{663})$

Step-by-step explanation:

Here, the total number of cards in a given deck = 52

let E : Event of drawing a first card which is King

Total number of kings in the given deck = 4

So, $P(E) = \frac{\textrm{The total number of king}}{\textrm{The total number of cards}}$ = $\frac{4}{52} = (\frac{1}{13} )$

Now, as the picked card is NOT REPLACED,

So, now the total number of cards = 52 - 1 = 51

Total number of queen in the deck is same as before = 13

let K : Event of drawing a second card which is queen

So, $P(K) = \frac{\textrm{The total number of queen}}{\textrm{The total number of cards}}$ = $(\frac{4}{51} )$

Now, the combined probability of picking first card as king and second as queen = P(E) x P(K) = $(\frac{1}{13}) \times(\frac{4}{51}) = (\frac{4}{663} )$

Hence, the simplified expression is $(\frac{4}{663})$

6 0

3 years ago

A theatre ticket costs £63 plus a booking fee of 3% what is the total price of the ticket

ryzh [129]

P=63+63(3/100)

p=63(1+3/100)

p=63(1.03)

p=$64.89

6 0

4 years ago

PLEASE HELP ITS URGENT!!<br> Given: △ABC is isosceles; 1 ≅ 3<br> Prove: AB || CD

Dmitrij [34]

Answer:

AB ║ CD. (Proved)

Step-by-step explanation:

See the attached diagram of the triangle.

It is given that Δ ACD is an isosceles triangle.

Therefore, AC = AD and ∠ ACD = ∠ ADC, ⇒ ∠ 3 = ∠ 4 .......... (1)

Again, given that ∠ 1 = ∠ 3 ........... (2)

Now, from equations (1) and (2) we can write, ∠ 1 = ∠ 4

Now, AB and CD are two straight lines and AD is the transverse line and hence, ∠ 1 and ∠ 4 are alternate angles that are equal.

Therefore, AB and CD are parallel straight lines and AB ║ CD. (Proved)

4 0

4 years ago

Find the three equation that have the solution

Elenna [48]

Answer:

B and C

i hope it is....thnk u

5 0

3 years ago

Read 2 more answers