Whats2+2÷2×8+4+5÷5×20

Mathematics

2 answers:

GREYUIT [131]3 years ago

8 0

It’s 20 I just did that problem earlier

emmasim [6.3K]3 years ago

7 0

either 100 or 34

so sorry if its wrong maybe i did my calculations wrong

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If 4y-4=16 then y= ?

algol [13]

Move the -4 to the right (+4 on both sides). now you have 4y=20. divide both sides by 4. y=5

4 0

3 years ago

Read 2 more answers

What is 859 under a thousand as a mixed number?

Semmy [17]

To convert the improper fraction $\frac{1000}{859}$ into a mixed number, you first want to divide the numerator (1000) by the denominator (859):
$1000 \div 859 = 1 R141$

The quotient, which is 1, will be your whole number part of your mixed number. The remainder, 141, will become the numerator of the fraction part of your mixed number. The original denominator of your improper fraction, 859, is still the denominator of your mixed number. So your mixed number form of your improper fraction is:
$\frac{1000}{859} = 1 \frac{141}{859}$

Your answer is $1 \frac{141}{859}$

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3 years ago

The produce manager at a market orders 10 lb of tomatoes, 20 lb of zucchini, and 40 lb of onions from a local farmer one week.

rewona [7]

Answer:

(A) $A=\left[\begin{array}{ccc}10&20&40\end{array}\right]$

(B) $B=\left[\begin{array}{ccc}11&22&44\end{array}\right]$

Step-by-step explanation:

The manager ordered 10 lb of tomatoes, 20 lb of zucchini, and 40 lb of onions from a local farmer one week.

(A)

Matrix A represents the amount of each item ordered. It is 1 × 3 matrix.

Then matrix A is:

$A=\left[\begin{array}{ccc}10&20&40\end{array}\right]$

(B)

Next week the manager increases the order of all the products by 10%.

Then the amount of new orders are:

Tomatoes $=10\times [1+\frac{10}{100}]=10\times1.10=11$

Zucchini $=20\times [1+\frac{10}{100}]=20\times1.10=22$

Onions $=40\times [1+\frac{10}{100}]=40\times1.10=44$

Th matrix B represents the amount of each order for the next week. Then matrix B is:

$B=\left[\begin{array}{ccc}11&22&44\end{array}\right]$

(C)

Add the two matrix A and B as follows:

$A+B=\left[\begin{array}{ccc}10&20&40\end{array}\right]+\left[\begin{array}{ccc}11&22&44\end{array}\right]\\=\left[\begin{array}{ccc}(10+11)&(20+22)&(40+44)\end{array}\right]\\=\left[\begin{array}{ccc}21&42&84\end{array}\right]$