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Alika [10]
2 years ago
7

On a field trip there were 5 girls for every 8 boys. how many girls attended the 130-student field trip?

Mathematics
2 answers:
VMariaS [17]2 years ago
5 0
Well there is no answer since you did not specify the amount of boy and girls on the field trip

postnew [5]2 years ago
4 0
50 girls attended the trip.
  80 boy + 50 girls = 130 total students
8x10 =80 
5x10=50 
 
multiply both by 10.
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Simone invests 1200 into two savings accounts. One account earns 4% annual interest and the other earns 5.9% annual interest. At
Allisa [31]

Answer: He invested $350 at 4% and $850 at 5.9%

Step-by-step explanation:

Let x represent the amount which he invested in the account earning 4% interest.

Let y represent the amount which he invested in the account earning 5.9% interest.

Simone invests 1200 into two savings accounts. One account earns 4% annual interest and the other earns 5.9% annual interest. This means that

x + y = 1200

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account earning 4% interest,

P = $x

T = 1 year

R = 4℅

I = (x × 4 × 1)/100 = 0.04x

Considering the account earning 5.9% interest,

P = $y

T = 1 year

R = 5.9℅

I = (y × 5.9 × 1)/100 = 0.059y

At the end of 1 year, Simon earned 64.15 in interest. it means that

0.04x + 0.059y = 64.15 - - - - - - - - -1

Substituting x = 1200 - y into equation 1, it becomes

0.04(1200 - y) + 0.059y = 64.15

48 - 0.04y + 0.059y = 64.15

- 0.04y + 0.059y = 64.15 - 48

0.019y = 16.15

y = 16.15/0.019

y = 850

x = 1200 - y = 1200 - 850

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7 0
2 years ago
The pressure and volume of an expanding gas are related by the formula PV^b=C, where b and C are constants (this holds in adiaba
bazaltina [42]

The dP/dt of the adiabatic expansion is -42/11 kPa/min

<h3>How to calculate dP/dt in an adiabatic expansion?</h3>

An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression

Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min

PVᵇ = C

Taking logs of both sides gives:

ln P + b ln V = ln C

Taking partial derivatives gives:

\frac{1}{P}\frac{∂P}{∂t}  + \frac{b}{V}\frac{∂V}{∂t} = 0

Substitutituting the values b, P, V and dV/dt into the derivative above:

1/7 x dP/dt +  1.5/110 x 40 = 0

1/7 x dP/dt +  6/11 = 0

1/7 x dP/dt = - 6/11

dP/dt = - 6/11 x 7

dP/dt = -42/11 kPa/min

Therefore, the value of  dP/dt is -42/11 kPa/min

Learn more about adiabatic expansion on:

brainly.com/question/6966596

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