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11111nata11111 [884]
3 years ago
12

What are the vertical and horizontal asymptotes of f (x) = StartFraction 2 x Over x minus 1 EndFraction?

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0

Answer:

horizontal asymptote at y = 2, vertical asymptote at x = 1

Step-by-step explanation:

We are given the following function:

f(x) = \frac{2x}{x - 1}

Horizontal asymptote:

The horizontal asymptote of a function is the limit of the function as the input, in this case x, goes to infinity. When we want to find the limit of x going to infinity of a fraction we consider the term with the largest exponent on both the numeration and the denominator. So

\lim_{x \rightarrow \infty} \frac{2x}{x - 1} = \lim_{x \rightarrow \infty} \frac{2x}{x} = \lim_{x \rightarrow \infty} 2 = 2

So there is a horizontal asymptote at y = 2

Vertical asymptote:

Vertical asymptotes happens at points outside the function domain.

In this question, we have a fraction, in which the denominator cannot be 0. So

x - 1 = 0 \rightarrow x = 1

Thus, there is a vertical asymptote at x = 1.

The correct option is:

horizontal asymptote at y = 2, vertical asymptote at x = 1

shepuryov [24]3 years ago
6 0

Answer:

B

Step-by-step explanation:

I got it right

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The answer is:  " -5/3 " ;  or, write as:  " -1 ⅔ " .
_____________________________________________
Explanation:
_____________________________________________

   (-5/6) + (-5/6) = (-5/6) <span>− (5/6) ;  

------>  {since: "adding a negative" is the same a "subtracting a positive"} ; 

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