Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
336 sq un
Step-by-step explanation:
The area of a rhombus is pq/2 where p and q are the diagonals.
you have:
p = 12 + 12 = 24
q = 18 + 10 = 28
so the formula would be:
24 * 28 / 2 = 336 sq un
Amount of water that the faucet leaks in 1 week = 42 gallons
That means Amount of water that the faucet in Kali's house leaks in 7 days = 42 gallons So The amount of water that the faucet in Kali's house leaks in 1 day = (42/7) gallons = 6 gallons Then The amount of water that the faucet in Kali's house leaks in 3 days = 6 * 3 gallons = 18 gallons
So it can said from the above deduction that the amount of water leaked by the faucet in Kali's house is 18 gallons.
hope this help .-.
Answer:
74
Step-by-step explanation:
Order of operations: PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)
5(9)+2(6) ÷ 3 + 
= 45+12÷ 3 +25
=45+4+25
=74
I think it's A.
The difference = x - 5, where x is Jamie's height.