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3 years ago

4(3+4)+6(9-1)-8=? pls any one helppppppppp me

Mathematics

2 answers:

Neko [114]3 years ago

4 0

Step-by-step explanation:

⠀⠀⠀⠀⠀⠀⠀⠀⠀

Rom4ik [11]3 years ago

3 0

$\huge\text{Hey there!}$

$\large\text{In order for you to SOLVE for THIS EQUATION you have to do is}\\\large\text{PEMDAS. Which simply means}\downarrow$

$\bullet\large\text{Parentheses}\\\bullet\large\text{Exponents}\\\bullet\large\text{Multiplication}\\\bullet\large\text{Division}\\\bullet\large\text{Addition}\\\bullet\large\text{Subtraction}$

$\large\text{Here is your steps to solving for your given equation}\downarrow$

$\large\text {4(3 + 4) + 6(9 - 1) - 8}\\\large\text{3 + 4 = 7}\\\large\text{4(7) + 6(9 - 1) - 8}\\\large\text{(9 - 1) = 8}\\\large\text{4(7) + 6(8) - 8}\\\large\text{4(7) = 28}\\\large\text{28 - 6(8) - 8}\\\large\text{6(8) = 48}\\\large\text{28 + 48 - 8}\\\large\text{28 + 48 = 76}\\\large\text{76 - 8 = \bf 68}\\\large\text{= \bf 68}\\\\\boxed{\boxed{\huge\text{Answer: \bf 68}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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Answer:

$92 \:cm^2$

Step-by-step explanation:

$Surface\:_{area}=2\times(\ell\times w +\ell \times h + w \times h)$

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$=2 \times (16+24+6)$

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2 years ago

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3 years ago

Example 24 In a school there are 20 teachers who teach mathematics or physil

Trava [24]

Answer:

The number of teachers who teach physics n(P) = 12

Step-by-step explanation:

Step(i):-

Given that the number of teachers who teach mathematics or physics

n(MUP) = 20

Given that the number of teachers who teach mathematics

n(M) = 12

Given that the number of teachers who teach both mathematics and physics

n(M∩P) = 4

Step(ii):-

By using n(A∪B) = n(A) + n(B) - n(A∩B)

n(M∪P) = n(M) +n(P) - n(M∩P)

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Answer:

1) 0, 180

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6) 0

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Step-by-step explanation:

1) sinx = 0

x = 0, 180, 360

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3 years ago

Help solving this math question

olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = $\frac{488,106,000-358,708,000}{2}$ = $\frac{129,398,000}{2}$ = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = $\frac{4,051,050}{5,921,379}$ = 0.6841,