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SSSSS [86.1K]
3 years ago
8

Two forces P and Q acting at a point at an angle have their resultant

Physics
1 answer:
nasty-shy [4]3 years ago
6 0

Answer:

Answer is given in this paper.

                                               <u><em>Thank You</em></u>

                                     Please mark me Brainlest.

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The magnetic field lines outside a bar magnet
n200080 [17]
The lines of magnetic field from a bar magnet form closed lines. By convention, the field direction is taken to be outward from the North pole and in to the South pole of the magnet.
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3 years ago
A solution is known as a homogeneous mixture because _[blank]_.
alekssr [168]

Answer:

The solute fully dissolves in the solvent

Explanation:

This is because for a solution to be called a homogeneous mixture, all the solute must be dissolved in the solvent, without the particles of the solute being visible in the solvent.

8 0
3 years ago
Gather data: Select Mercury from the Solar system menu at left. Turn on Additional data. In the table below, record Mercury’s Ma
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Answer:

volume of substance of weight of mercury is 13593 kilograms

3 0
3 years ago
An object with an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second squared in the direction
leva [86]

Answer:

6 m/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 4 m/s

Acceleration (a) = 2 m/s²

Distance (s) = 5 m

Final velocity (v) =?

The final velocity of the object can obtained as shown below:

v² = u² + 2as

v² = 4² + (2 × 2 × 5)

v² = 16 + 20

v² = 36

Take the square root of both side.

v = √36

v = 6 m/s

Therefore, the final speed of the object is 6 m/s.

8 0
3 years ago
In an experiment, it took 300s to increase the temperature of 0.1kg of the liquid from 25°C to 50°C. During this period, the ene
klemol [59]

Answer:

<h2>4000 \textbf{J}\text{ }\textbf{kg}^{\textbf{-1}}\text{ }\textbf{K}^{\textbf{-1}} </h2>

Explanation:

        The temperature of 0.1 kg of liquid rises from 25°C to 50°C in 300 sec. Energy of 13,600 J was supplied during this time. Appartus was losing energy at the rate of 12 J/sec.

       Let us assume the Specific heat capacity as s.

      As there is no state change from liquid to gas, only Specific heat capacity is involved. Also, work done is approximately zero because volume does not change much. So,

       Energy gained = Energy required to rise the temperature

       Energy gained by liquid = 13600\text{ }J-(300\text{ }sec)\times(12\text{ }\frac{J}{sec})=10000\text{ }J

       10000\text{ }J=m\times s\times\Delta T=(0.1\text{ }kg)\times(s)\times(323K-298K)=2.5s\text{ }kgK\\s=4000\text{ }\frac{J}{kg.K}

∴ Specific heat capacity of liquid = 4000 \frac{J}{kg.K}

4 0
3 years ago
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