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Crank
2 years ago
9

I don’t understand this

Mathematics
1 answer:
Dahasolnce [82]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Statement 1: If JK and LM bisect each other then, they divide each other in 2 equal parts.

So,

JP = PK [Because of statement 1]

MP = PL [Because of statement 1]

∠JPM = ∠LPK [Because they are vertically opposite angles]

So, ΔJPM ≅ to ΔKPL [By SAS congruence criteria of triangle]

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Plz help Events A and B are independent. Let event A be the event that a person chooses and buys a certain pear from the grocery
kompoz [17]

Hi all

Answer:

I had this question on my MAP testing just today, and I answered with

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2 years ago
11. Keng creates a painting on a rectangular canvas with a width that is four inches longer
GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

We multiply the length and height to get the area

area = (length)*(height)

area = (h+4)*(h)

area = h(h+4)

area = h^2 + 4h .... apply the distributive property

The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

area = h( x ) + 10( x )

area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

The units for the area are in square inches.

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3 years ago
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Arisa [49]

Step-by-step explanation:

√a = 1√a so we can solve them easily:

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g) √2+2√2= 3√2

j) √5+5√5 - 3√5 = 3√5

k) 2√3 + √3 - 5√3= -2√3

I) 5√11 + 7√11 - √11 = 11√11

7 0
2 years ago
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