JUST ANSWER MY QUESTION I KNOW ABOUT THE BOTS

-5(-2) =<br><br> Need help ASAP (too lazy to actually do the work )

just olya [345]

I think the answer is 10

4 0

3 years ago

Suppose that Sin(θ)=5/13 and cos(θ)=-12/13. Find the value of tan(θ), cot (θ), CSC (θ), and sec (θ). Find the value of tan(2θ)

horrorfan [7]

Answer:

Because θ lies in quadrant II, 2θ must lie in quadrant IV. This means the tangent of 2θ is negative.

The adjacent side to θ is 7 because √(25²-24²)=7, so tanθ=7/24.

The double angle formula for tangent is tan 2θ = (2 tan θ) / (1 − tan² θ).

Substituting the value for tanθ in and keeping in mind that this is in quadrant IV, we get tan 2θ = -(2(7/24)/(1-(7/24)²)).

Simplified, this becomes tan 2θ = -336/527.

Therefore, the answer is C. -336/527.

5 0

3 years ago

Nancy is making cookies for a bake sale. She needs a total of 4 pounds of chocolate chips. She has a 28-ounce bag of chocolate c

Westkost [7]

How many ounces are in a pound? 16! SO 16 times 4 = 64. So Nancy needs 64 ounces in all. So 28 plus 10 = 38 that's still not enough, so lets add some more 38 plus 10 = 48 still not enough, add some more 48 plus 10 plus 10 = 68. So lets add up how many bags we need. So in all with her 28 that she already has, we need 4 bags.

4 0

3 years ago

hammer [34]

Answer:

The test statistic is z=2.5.

The null hypothesis is rejected.

There is enough evidence to support the claim that more than 10% of the 16 ounce cups are underfilled.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that more than 10% of the 16 ounce cups are underfilled.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.1\\\\H_a:\pi>0.1$

The significance level is assumed to be 0.05.

The sample has a size n=100.

The sample proportion is p=0.18.

$p=X/n=18/100=0.18$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.1*0.9}{100}}\\\\\\ \sigma_p=\sqrt{0.001}=0.03$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.18-0.1-0.5/100}{0.03}=\dfrac{0.075}{0.03}=2.5$

This test is a right-tailed test, so the P-value for this test is calculated as:

$P-value=P(z>2.5)=0.006$

As the P-value (0.006) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that more than 10% of the 16 ounce cups are underfilled.

7 0

3 years ago

Jill bought a bag that 24 starbursts in it. Then she ate 1/3 of them. What is the total number of starbursts that Jill ate?

stealth61 [152]

She ate a total of 8 starbursts

7 0

3 years ago