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geniusboy [140]
3 years ago
14

There are 751 identical plastic chips numbered through 751 in a box.

Mathematics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

1.1331

Step-by-step explanation:

Divided 100 by 751

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What is the solution to y=x+2 and x=-3
Wewaii [24]

Answer:

x=-3, y=-1. (-3, -1).

Step-by-step explanation:

y=x+2

y=-3+2=-1

4 0
3 years ago
a local newspaper assigns a rating between 1 and 10 to every book and movie it reviews. Victor gathered data about five titles w
Nookie1986 [14]

The points that represent this data are shown in the image attached below.

<h3>What is a scatter plot?</h3>

A scatter plot is a type of graph which is used for the graphical representation of the values of two variables, with the resulting points showing any association (correlation) between the data set.

Based on the information provided in table above, the points that represent this data are shown in the image attached below.

Read more on scatterplot here: brainly.com/question/6592115

#SPJ1

3 0
2 years ago
From a deck of five cards numbered 2, 4, 6, 8, and 10, respectively, a card is drawn at random and replaced. this is done three
Serga [27]

Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, 2+2+8 = 12, and there are no other possibilities, unless you consider the various permutations of the terms.

So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.

Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.

So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of 5 \times 5 \times 5 = 5^3 = 125 possible triplets.

Once we know the "good" cases and the total number of possible cases, the probability is simply computed as

P = \cfrac{\text{number of favourable cases}}{\text{number of all possible cases}} = \cfrac{3}{125}

3 0
3 years ago
A factory robot recently examined some bulbs, of which 2 were flawed and 18 were not. If 30 more bulbs are examined, predict how
Oksanka [162]

Answer:

3 bulbs should be flawed

Step-by-step explanation:

2+ 18 = 20

20 bulbs were examined

2/20  = 1/10 were flawed

looking at the next 30 bulbs

30 * 1/10 = 3

3 of the next 30 bulbs should be flawed


5 0
3 years ago
The photo down below will show you what I need help with.​
Irina18 [472]

Answer:

\frac{x+7}{3} (the second option)

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
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