3 years ago

Please help——- Geometry problem Thank you.

Mathematics

1 answer:

Akimi4 [234]3 years ago

7 0

Answer:

Step-by-step explanation:

sinA = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{s\sqrt{3} }{2s}$ ( cancel s on numerator/ denominator ), then

sinA = $\frac{\sqrt{3} }{2}$ → b

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