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3 years ago

8

Trough: (2,2) parallel to y=x+4

1 answer:

Vlada [557]3 years ago

7 0

Answer:

y = x

Step-by-step explanation:

The slopes of parallel lines are the same, so we know the equation will be ...

y = x + constant

We can find the constant by using the given point's values for x and y:

2 = 2 + constant

Obviously, the constant is zero.

The equation of the parallel line through (2, 2) is y = x.

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-2 8/9 as a decimal and how to get it

slavikrds [6]

Answer: -2.88889

Step-by-step explanation:

calculate the approimate value

8 0

3 years ago

What is 24.21 written in expanded form?

vodomira [7]

Answer:

(2 x 10) + (4 x 1) + (2 x 0.1) + (1 x 0.01)

Step-by-step explanation:

4 0

3 years ago

Ten times the sum of half a number and 6 is 8.

Sedaia [141]

That would be

$10( \frac{1}{2} n + 6) = 8$
$\frac{1}{2} n+6= \frac{8}{10}$
$.5n + 6 = .8$
$.5n = -5.2$
$n=-2.6$

Hope that helps :)

8 0

3 years ago

Help asap my last question GIVING BRAINLIST!!!!

Alex

Answer:

1) $x < 0$

2) $x > 0$

3) $x < 10$

4) $x < -\frac{31}{55}$

5) $x \geq 0$

6) $x \geq -1$

Step-by-step explanation:

1) $-3 > 2x -3$

$2x- 3 < -3$

$2x - 3 + 3 < -3 +3$

$2x < 0$

$\frac{2x}{2} < \frac{0}{2}$

$x < 0$

2) $5 > -x + 5$

$-x + 5 < 5$

$- x + 5 -5 < 5 - 5$

$-x < 0$

$\frac{-x}{-1} < \frac{0}{-1}$

$x > 0$

3) $\frac{x}{5} -2 < 0$

$5 \times (\frac{x}{5} - 2 ) \times 5 < 0$

$x - 10 < 0$

$x -10 + 10 < 0 +10$

$x < 10$

4) $-5x + 11 > 31$

$-5x \cdot 11 < 31$

$-55x < 31$

$\frac{-55x}{-55} > \frac{31}{-55}$

$x < -\frac{31}{55}$

5) $\frac{1}{2}x - 4 \geq -4$

$\frac{1}{2}x -4 +4 \geq -4 +4$

$\frac{1}{2}x \geq 0$

$\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }$

$x \geq 0$

6) $-4x + 2 \leq 6$

$-4x +2 - 2 \leq 6 -2$

$-4x < 4$

$\frac{-4x}{-4} \leq \frac{4}{-4}$

$x \geq -1$

6 0

3 years ago

Determine the equation of the line that goes through points (1.1) and (3.7).

ValentinkaMS [17]

Answer:

The equation of the line that goes through points (1,1) and (3,7) is $\mathbf{y=3x-2}$

Step-by-step explanation:

Determine the equation of the line that goes through points (1,1) and (3,7)

We can write the equation of line in slope-intercept form $y=mx+b$ where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=1, y_1=1, x_2=3, y_2=7$

Putting values and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{7-1}{3-1}\\Slope=\frac{6}{2}\\Slope=3$

We get Slope = 3

Finding y-intercept

y-intercept can be found using point (1,1) and slope m = 3

$y=mx+b\\1=3(1)+b\\1=3+b\\b=1-3\\b=-2$

We get y-intercept b = -2

So, equation of line having slope m=3 and y-intercept b = -2 is:

$y=mx+b\\y=3x-2$

The equation of the line that goes through points (1,1) and (3,7) is $\mathbf{y=3x-2}$

4 0

3 years ago