We will conclude that:
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
<h3>
Comparing the domains and ranges.</h3>
Let's study the two functions.
The exponential function is given by:
f(x) = A*e^x
You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:
y > 0.
For the logarithmic function we have:
g(x) = A*ln(x).
As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

So the range of the logarithmic function is the set of all real numbers.
<h3>So what we can conclude?</h3>
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
If you want to learn more about domains and ranges, you can read:
brainly.com/question/10197594
Actually Welcome to the Concept of the Angles,.
Since,the AE is a angle bisector, hence, BAE = EAC simply.
hence we equate them..
===> x+ 30 = 3x - 10
==> 3x - x = 30 + 10
==> 2x = 40
==> x = 20°
hence the major angle EAC = 3(20)-10 = 60-10 = 50°
hence, angle EAC = 50°
K= 16
25x^2+40x+16x comes to be (5x+4)^2.
If you add a constant to the original equation, you are actually shifting up or down
Since the constant is positive, you are shifting the graph 20 units up