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2 years ago

Which expression is equivalent to

Mathematics

1 answer:

Yuliya22 [10]2 years ago

6 0

Respuesta A

1+2(x-1)

1+2x-2
2x-1

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My number has a tens digit that is 8 more than the ones digit. Zero is not one of my digits. Write the 2-digit number that match

pochemuha

Answer:

The number is 91

Step-by-step explanation:

Let x be the ones place digit and y be the tens place digit,

Then the number would be 10y + x,

We have,

y - x = 8

Possible values of y and x = { (8, 0), (9, 1) }

∵ 0 is not the digit of the number,

Hence, y = 9 and x = 1

Therefore, required number = 10(9) + 1 = 90 + 1 = 91

6 0

3 years ago

Read 2 more answers

castortr0y [4]

I'm not going to say I'm 100% correct.

6 0

3 years ago

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago

Is 3y^2-2y already simplified

geniusboy [140]

Yes it is already simplified because there is nothing else that you are able to do to it.

4 0

3 years ago

Read 2 more answers

Pls help I’m failing<br> Is it rational or<br> Irrational show your work

KengaRu [80]

it's rational number because it's in the form of p/q

8 0

2 years ago