Which number of simulation trials would be likely to produce results that areClosest to the actual probability
1 answer:
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Answer <u>(assuming it can be in slope-intercept form)</u>:
Step-by-step explanation:
1) First, find the slope of the line by using the slope formula, . Substitute the x and y values of the given points into the formula and solve:
So, the slope is .
2) Now, use the point-slope formula to write the equation of the line in point-slope form. Substitute real values for the
,
, and
in the formula.
Since represents the slope, substitute
in its place. Since
and
represent the x and y values of one point the line intersects, choose any one of the given points (either one is fine, it will equal the same thing at the end) and substitute its x and y values into the formula as well. (I chose (0, -7), as seen below.) Then, isolate y to put the equation in slope-intercept form and find the following answer:
Answer:
P( top two horses are predicted incorrectly in incorrect order)
=
Step-by-step explanation:
In the horse race the outcome can be predicted in 5! = 120 ways.
Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.
Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5
so the second horse can be predicted to be in place from 1 to (k - 1)
So, the top two horses can be predicted incorrectly in incorrect order
in = 10 ways
and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.
Hence ,
P( top two horses are predicted incorrectly in incorrect order)
=
=