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masya89 [10]
2 years ago
5

What is x/y ? Help pls

Mathematics
1 answer:
algol [13]2 years ago
8 0

Answer:

ok I really suck at math, but I think you may have to multiply the x/y to get the whole area of the circle. so maybe itd be 10x25. I'm sorry if this isnt correct

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(2n – 3)(5n+6)<br> How do I solve this ?
nalin [4]

Answer:

Step-by-step explanation:

(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)

=2n*5n + 2n*6 -3*5n + (-3)*6

=10n² + 12n - 15n - 18

= 10n² -3n - 18

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3 years ago
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Can anyone solve this? will give brainliest if correct.
miv72 [106K]

Answer:

  • See below

Step-by-step explanation:

<u>The missing reasons are:</u>

  • 1. k. Given
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8 0
2 years ago
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What is six ninths minus one third
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Can someone pls help me? I’m confused!
OleMash [197]

Answer:

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3 years ago
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Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

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