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lbvjy [14]
2 years ago
9

Classify 3

Mathematics
2 answers:
Rom4ik [11]2 years ago
7 0
A because 3 is rational, and it’s a natural and whole number because it’s about 0. It’s an integer because integers include negative and positive numbers.
Hunter-Best [27]2 years ago
5 0
It c I had this question I know it's c
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tom is making a rectangular garden. he decides to make the garden 30 ft long by 15 ft wide. Later, tom decides to keep the lengt
UkoKoshka [18]
Width=25 got me m; iyyyyg
3 0
3 years ago
Kelly was asked to determine whether △KLN is congruent to △MNL. She noted that KL ≅ MN, LM ≅ KN, and that the three pairs of cor
Art [367]

Answer:

<h2>Kelly is wrong, with this congruent parts, we can conclude that triangles are congruent.</h2>

Step-by-step explanation:

To demonstrate congruent triangles, we need to use the proper postulates. There are at least 5 postulates we can use.

  • Angle-Angle-Side Theorem (AAS theorem).
  • Hypotenuse-Leg Theorem (HL theorem).
  • Side-Side-Side Postulate (SSS postulate).
  • Angle-Side-Angle Postulate (ASA postulate).
  • Side-Angle-Side Postulate (SAS postulate).

In this case, Kelly SAS postulate, because the corresponding sides-angles-sides are congruent, i.e., KL ≅ MN and LM ≅ KN, also, all corresponding angles are congruent.

So, as you can see, only using SAS postulate, the congruency can be demonstrated. (Refer to the image attached to see an example of SAS postulate)

8 0
3 years ago
Being fun again who whants points here is a question you'll get 50 points
stich3 [128]

Answer:

0.46

Step-by-step explanation:bark brainliest plz

8 0
3 years ago
Read 2 more answers
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
Read 2 more answers
Find x. Pleaseee help
hoa [83]

Answer:

x=35

Step-by-step explanation:

plz mark me as brainliest

4 0
3 years ago
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