Given that:
CI = ₹408
years = 2 years
Rate of interest = 4%
A = P{1+(R/100)}^
A-P = p{1+(R/100)}^n - P
I = P[1+(R/100)}^n - 1]
408 = P[{1+(4/100)²} - 1]
= P[{1+(1/25)²} - 1]
= P[(26/25)² - 1]
= P[(676/625) - 1]
= P[(676-625)/625]
408 = P(51/625)
P = 408*(625/51)
= 8*625 = 5000
Sum = 5000
Simple Interest (I) = (P*R)/100
= 5000*2*(4/100)
= 50*2*4 = 400
From the given above options, option (a) ₹400 is your correct answer.
On a typical number line, we have basically two directions that we can move on. Either to the left where the numbers are negative, of to the right where the numbers are positive.
Given that point E has a coordinate of 1 on a number line, and we are told that the distance between E and another point on the number line is 11 (EG), the possible coordinates of point G are two (either we are moving to the right or to the left). Therefore, possible coordinates of G are:
1 - 11 = -10 (to the left)
1 + 11 = 12 (to the right
Answer:
x=1 y=-5
Step-by-step explanation:
7(5x-2y=15) ---> 35x-14y=105
2(7x+7y=-28) --> + <u>14x+14y=-56</u>
49x=49 --->x=1
5(1)-2y=15 ---> 5-2y=15 ---> -2y=10 ---> y=-5
4 times 4 which is 8 so 8 times 4 which is 32 so divide that by 138 but divide the 138 first and you will get 17.25?
