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2 years ago

Should the quadratic formula be used to solve this question explain.x^2+4x-3=0

Mathematics

1 answer:

garik1379 [7]2 years ago

8 0

Answer:

Yes

Step-by-step explanation:

This equation does not factorise, so quadratic equation will be useful. It is easier than other methods that can be applied to this equation.

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Have you ever been swimming in a pool, and your eyes were red when you get out? This means the chemicals in the pool were not ad

soldier1979 [14.2K]

pH = f(x) = -log₁₀x

1. Graphs

I used Excel to calculate the pH values and draw the graphs (see the Figure).

f(x) and f(x) +1 are plotted against the left-hand axis, while f(x+ 1) is plotted against the expanded right-hand axis.

The points at which pH = 0 and pH = 1 are indicated by the large red dots.

2. x = 0.5

When x = 0.5, pH ≈0.30. The point is indicated by the red diamond.

3. Transformations

(a) ƒ(x) = -log(x) + 1

This function has no y-intercept, because log(0) is undefined.

(b) ƒ(x +1) = -log(x + 1)

f(0) = -log(0 + 1) = -log(1) = 0

This function has a y-intercept at (0,0).

hope this helps please mark me brainliest!

3 0

2 years ago

The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we

Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

Sigma, σ = 0.200 kg

Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13$

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

Test statics :

$Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}}$

$Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}}$

$=\frac{1.82}{0.04}$

= 45.5

P-value = 2 x P(Z > 45.5)

= 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0

2 years ago

Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was $43.5

Inga [223]

Using the Empirical Rule, it is found that:

a) Approximately 99.7% of the amounts are between $35.26 and $51.88.
b) Approximately 95% of the amounts are between $38.03 and $49.11.
c) Approximately 68% of the amounts fall between $40.73 and $46.27.

------------

The Empirical Rule states that, in a bell-shaped distribution:

Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.

-----------

Item a:

$43.5 - 3(2.77) = 35.26$