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AURORKA [14]
3 years ago
12

Let x represent the side length of a square. Find a regular polygon with side length x whose perimeter is twice the perimeter of

the square. Find a regular polygon with side length x whose perimeter is three times the length of the square
Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

Step-by-step explanation:t55

An octagon has 8 sides. If each of them has a length of x, then the perimeter is 8x which is twice the perimeter of the square. (The square has a perimeter of 4x)

A dodecagon is a 12 sided regular polygon. It will have 12 sides all of which are equal to x. Since the square has a perimeter of 4x and the dodecagon has a perimeter of 12x the perimeter of the dodecagon is 3 times that of the given square.

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Please help me tahank you so much
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We know that a triangle adds up to 180 degrees.

Here, 130 is a vertical angle so on the opposite side the triangle makes, it is also 130. Then we could add 130 to 25

130 + 25 = 155

Now let’s subtract this from 180.

180 - 155 = 25.

X is a supplementary angle to 25 so subtract 25 from 180.

180 - 25 = 155

X = 155.
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