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PIT_PIT [208]
2 years ago
8

A restaurant is doing a special on burgers. If the home team get a sack, the next day, burgers will cost$1

Mathematics
1 answer:
lyudmila [28]2 years ago
5 0

ans: 257,256.59

if it was sold for $3.99

it would have been 86,047 × $3.99 = 343,303.59 and it was sold for $1 instead so automatically it's $86,047

therefore

343, 303.59

-86, 047 which is equal to a loss of $257, 256.59

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Is having a multiplication sign outside the parentheses the same as not?
katrin2010 [14]
I believe it's the same
8 0
3 years ago
Read 2 more answers
Please help me with this. Just have to write the equation. If you can solve, then you get brainliest guaranteed!
Temka [501]

x = player1

y = player 2

z = player 3

y = 2x  or 1/2 y =x

y = z-10  or z = y+10

x+y+z=70

substitute x= 1/2 y and z = y+10 into the above equation

1/2y + y + y+10 = 70

2.5 y + 10 = 70

subtract 10 from each side

2.5 y = 60

divide by 2.5 on each side

y = 60/2.5

y =24

x = 1/2 y

x = 1/2 *24 = 12

z = y+10 = 24+10 = 34

The three players scored 12, 24, 34


4 0
3 years ago
Read 2 more answers
Is -8-2(3+2n)+7n equivalent to -30-13n. Explain why or why not.
seropon [69]

No, -8 - 2(3 + 2n) + 7n is not equivalent to -30 - 13n

Step-by-step explanation:

Let us revise the operation of the negative and positive numbers

  • (-) + (-) = (-)
  • (-) × (-) = (+)
  • (-) + (+) = the sign of greatest [(-) if the greatest is (-) or (+) if the greatest is (+)]
  • (-) × (+) = (-)
  • (-) - (+) = (-)
  • (+) - (-) = (+)

∵ The expression is -8 - 2(3 + 2n) + 7n

- Simplify it

∵ 2(3 + 2n) = 2(3) + 2(2n) = 6 + 4n

∴ -8 - 2(3 + 2n) + 7n = -8 - (6 + 4n) + 7n

- Multiply the bracket by (-)

∴ -8 - (6 + 4n) + 7n = -8 - 6 - 4n + 7n

- Add the like terms

∴ -8 - (6 + 4n) + 7n = (-8 - 6) - 4n + 7n

∴ -8 - (6 + 4n) + 7n = -14 + 3n

∴ -8 - 2(3 + 2n) + 7n is equivalent to -14 + 3n

∵ -14 + 3n ≠ -30 - 13n

∴ -8 - 2(3 + 2n) + 7n is not equivalent to -30 - 13n

No, -8 - 2(3 + 2n) + 7n is not equivalent to -30 - 13n

Learn more:

You can learn more about the directed numbers in brainly.com/question/10364988

#LearnwithBrainly

8 0
3 years ago
16d + 20c + 5d -7 - 8c - 7d + 3 Evaluate the expression if: d= -3 and c= 4
IrinaK [193]

Answer:

2

Step-by-step explanation:

d.

16x-3= -48

5x-3= -15

-7x-3= 21

=-42

c.

20x4= 80

-8x4= -32

= 48

-7+3= -4

3 0
2 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
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