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3 years ago

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An investment grows according to the exponential equation y = 15,000 · 1.07x, where x is the number of years invested. Which of

the following statements is true?
A. The investment will continue to grow at a rate of 7% per year compounded quarterly.
B. The investment will increase by $1050 per year.
C. The investment will more than double within 12 years.
D.The investment will triple within 15 years

1 answer:

Nikolay [14]3 years ago

5 0

The option c is the answer because
2p=p (1.07)^x
2=1.07^x
Solve for x
X=log(2)÷log(1.07)
x=10 years the amount will be doubled after 10 years
But your option says the investment will (more) than double with (12) years
So it's correct

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1.25

Step-by-step explanation:

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Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

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substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

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Point:

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Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

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$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

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3 years ago

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sukhopar [10]

Answer:

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Step-by-step explanation:

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Therefore, option A is the correct choice.

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