1 2/5 as an improper fraction
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Let's assume
height of building in Makkah as x
since, the building in Dubai is 745 feet taller than the building in Makkah
So, the height of the building in Dubai is x+745
Taipei's building is 301 feet shorter than Makkah's
so, Taipei's building height is x-301
now, we are given
The combined height of the world's three tallest buildings is 6,360 feet
sum of all three heights must be 6360
now, we can solve for x
Combine like terms
Subtract both sides by 444
Divide both sides by 3
so,
height of building in Makkah is 1972 feet
the height of the building in Dubai is 1972+745=2717
Taipei's building height is 1972-301=1671
Hence,
height of building in Makkah is 1972 feet
the height of the building in Dubai is 2717 feet
Taipei's building height is 1671 feet..................Answer