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N76 [4]
3 years ago
14

1 2/5 as an improper fraction

Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0
Answer: 7/5. . . . .
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What is the solution of the inequality shown below
Eduardwww [97]

Answer:

there is no inequality..

Step-by-step explanation:

5 0
3 years ago
6.3 x 10^14<br><img src="https://tex.z-dn.net/?f=6.3%20%5Ctimes%20%20%7B10%7D%5E%7B14%3F%7D%20" id="TexFormula1" title="6.3 \tim
Nutka1998 [239]

I'm assuming you're looking to find the expanded form of the number?

This number is in scientific notation. The easiest way to convert it to a normal number is to move the decimal place 14 to the right. I've attached a picture showing how to do this. You should get 630,000,000,000,000

There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.

For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old

Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)

7 0
3 years ago
Solve the Fahrenheit equation for Celsius
horrorfan [7]
The first step you should do is subtract 32 from both sides so your answer will turn out like this -

F = (9/5) C + 32
- 
F - 32 = (9/5)

Then we will multiply both sides by 5. 

5 ( F - 32 ) = 9 C

Divide both sides by 9 to isolate C.

(5/9)  ( F - 32 ) = C

So the answer is :

C = (5/9) ( F - 32 )

Hope this helps :)

7 0
3 years ago
Read 2 more answers
the populatipn of a school of fish increases at a rate of 18% a Month. There are currently 500 fish in the school.
ruslelena [56]
You first must find the 18% of the fish population.

You multiply 500 by .18 . You are supposed to get 90.

90 is the 18% fish increase.

Then you just add 500 + 90 and you will get 590 fish that are now in the school.
8 0
3 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
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