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kupik [55]
2 years ago
7

Geometry, please answer question ASAP

Mathematics
2 answers:
vladimir1956 [14]2 years ago
7 0

Answer:

i think 60 degree is the answer

pantera1 [17]2 years ago
6 0

Answer:

72°

Step-by-step explanation:

There are 5 petals , so

angle of rotation = 360° ÷ 5 = 72°

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Find the slope that is PARALLEL and PERPENDICULAR to the equation of the line y = -1/2x+6.
kifflom [539]

Answer:

parallel: -1/2

perpendicular: 2

Step-by-step explanation:

lines that are parallel have the same slope because they never intersect

lines that perpendicular, have the opposite reciprocal slope.

y = mx + b

where m is the slope

y = -1/2x + 6

-1/2 is the slope.

the slope in the equation given: -1/2

the slope parallel to the line given : -1/2

the slope perpendicular : opposite reciprocal, so the opposite of -1/2 is 1/2 and the reciprocal of 1/2 is 2.

3 0
2 years ago
Sally buys a hang bag. There was a discaount of 35percent . If Sally paid $56.80 what was the original price?
Ksju [112]
Discount = 35%
Percentage after discount = 100% - 35% = 65%

65% = $56.80
1% = $0.8738
100% = $87.38

Answer: The original price is $87.38
4 0
2 years ago
Read 2 more answers
Rentite in simplest terms: - 10(9c – 7c+8) - 80​
zhannawk [14.2K]

Answer:

-20c-160

Step-by-step explanation:

-10(9c-7c+8)-80

-10(2c+8)-80

-20c-80-80

-20c-160

8 0
3 years ago
Read 2 more answers
How can you quickly determine the number of roots a polynomial will have by looking at the equation?
Goryan [66]
First, you need to get delta which is b squared minus 4ac. If delta is higher than cero, the polynomial has two solutions, if it is less, the polynomial has no real solutions and if it is the same, it has one solution.
Although that is only for second grade ecuations
7 0
3 years ago
Read 2 more answers
Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A
liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality \sin ^2\theta +\cos ^2\theta \geq 1

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

\sin \theta = side opposite to \theta/hypotenuse

\cos  \theta = side adjacent to \theta/hypotenuse

\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta

\cos  \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta

So, coordinates of A = \left ( \cos \theta ,\sin \theta  \right )

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by x^2+y^2=1

Put (x,y)=\left ( \cos \theta ,\sin \theta  \right )

\cos ^2\theta +\sin ^2\theta =1

So, (x,y)=\left ( \cos \theta ,\sin \theta  \right ) satisfies the equation x^2+y^2=1

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) inside the circle, \cos ^2\theta +\sin ^2\theta

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) outside the circle, \cos ^2\theta +\sin ^2\theta >1

So, only points on the circle satisfy the given inequality.

4 0
2 years ago
Read 2 more answers
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