Answer:
a=1
b=2
c=-8
y-intercept: (0, -8)
Line of symmetry calculation: x = -2/(2*1)
Line of symmetry: -1
Opens up because a > 0
Minimum
Vertex: (-1, -9)
Domain: -∞ < x < ∞ (no domain constraints)
Range: [-9, ∞]
Step-by-step explanation:
Answer:
10.25
Step-by-step explanation:
The slope of AC is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (-4 -1)/(3 -(-1)) = -5/4
Then the slope of CB is the opposite reciprocal, 4/5. The equation of line CB in point-slope form is ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
y -(-4) = 4/5(x -3) . . . . line CB
When y = 1 (to match the y-value of A), then ...
1 +4 = 4/5(x -3)
5(5/4) = (x -3) . . . . . multiply by 5/4
6.25 +3 = x = 9.25 . . . . add 3
Point B is (9.25, 1).
The length of the hypotenuse is ...
9.25 -(-1) = 10.25
Hello!
695 - 7x = 140
-7x = 140 - 695
-7x = -555
-x = -79.29
x = 79.29
I hope this helps you! Have a lovely day!
- Mal
Answer:
116
Step-by-step explanation
Its parallel so it's gonna be the same... so X= 116
Answer:
0.833
Step-by-step explanation:
1. locate which vertical column of the graph we are referring to:
2. calculate the total number of trials student 7 did:
- if in 5 trials the tack landed point-up, and in 1 trial the tack did not land point-up, the total number of trials is 6
- 5 + 1 = 6
3. refer back to the question:
- the question states: "what is the experimental probability that the tack lands point-up"
4. interpret the graph:
- of the 6 trials student 7 underwent, the graph tells us that 5 landed point-up.
- therefore the experimental probability of a tack landing point up is 5/6 (in 5 out of the 6 trials, the tack landed point-up)
5. converting from fraction to decimal:
- all the given answers are given in decimal form, whilst our current answer (5/6) is in fraction form.
- to convert to decimal form, simply divide the top number by the bottom number
- 5 ÷ 6 = 0.833
therefore, the experimental probability that the tack will land point-up, is 0.833
hope this helps :)
