Answer:
part 1) 0.78 seconds
part 2) 1.74 seconds
Step-by-step explanation:
step 1
At about what time did the ball reach the maximum?
Let
h ----> the height of a ball in feet
t ---> the time in seconds
we have

This is a vertical parabola open downward (the leading coefficient is negative)
The vertex represent a maximum
so
The x-coordinate of the vertex represent the time when the ball reach the maximum
Find the vertex
Convert the equation in vertex form
Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point 
therefore
The time when the ball reach the maximum is 25/32 sec or 0.78 sec
step 2
At about what time did the ball reach the minimum?
we know that
The ball reach the minimum when the the ball reach the ground (h=0)
For h=0



square root both sides


the positive value is

9514 1404 393
Answer:
c) 16,500 m³
d) 277,088 mm³
a) V = LWH
b) V = πr²h
Step-by-step explanation:
The relevant volume formulas are ...
- rectangular pyramid: V = 1/3LWH
- cylinder: V = πr²h
- rectangular prism: V = LWH
__
13c. The pyramid formula above tells us the volume is ...
V = 1/3(60 m)(15 m)(55 m) = 16,500 m³
__
13d. The cylinder formula above tells us the volume is ...
V = π(35 mm)²(72 mm) ≈ 277,088 mm³ ≈ 277 mL
__
14a. The shape appears to be a rectangular prism, so its volume is given by the formula ...
V = LWH . . . . . where L, W, H represent the length, width, and height
__
14b. The volume of a cylinder is given by the formula ...
V = πr²h . . . . . where r, h represent the radius and height (length)
Answer:7.5
Step-by-step explanation: cause I looked it up lol
The surface area is 72ft^2
hope this helped!