Answer:
582=-28-2287u272y7329=7373+272387##82838-78338=&*27882029··⇔㏒㏑∞°²³¥378c730+8383749=0891829.9279739383/03980339.83883383383)73837
Step-by-step explanation:
I don’t think you can delete questions
Answer:
0.5
Step-by-step explanation:
This is an example of mutually exclusive event in which two or more events cannot occur at the same time or in a single performance.
Therefore, the probability the number of cars entering the roadway is between 4 and 6 cars per minute (inclusive) implies that it is either 4, 5 or 6 cars enter in a minute. Since we have an average of 6 cars per minute, the probability of each of the event occurring is 1/6. This can therefore be calculated as follows:
P(4 or 5 or 6) = (1/6) + (1/6) + (1/6)
= 3/6
= 1/2
= 0.5
Therefore, the probability the number of cars entering the roadway is between 4 and 6 cars per minute (inclusive) is 0.5.
