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Katen [24]
3 years ago
11

Álgebra 2 need help

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

first term = -1/5

I cant see part b (sorry its too blurry)

thirteenth term = -0.2

part d: -19a/95a -0.2a

Step-by-step explanation:

socratic

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mr farmer rectangular land measures 2000 meters by 3000 meters. if he walks around the perimeter of his land, how far does he wa
Travka [436]

Answer:

10000 meters

Step-by-step explanation

To find perimeter you add the length of each side of the shape. Since the land is a rectangle there are two pairs that are parrallel, being 2000 and 3000. Making the distance 2000 + 2000 + 3000+ 3000 = 10000

Hope this helps!

4 0
3 years ago
Rewrite the expression 7 to the -2 power
iris [78.8K]

Answer:

1/49

Step-by-step explanation:

7^-2

1/49

7^2 is usually 49 for negative exponents just flip it

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take a screenshot, then copy and paste it to your question

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A circle has a diameter of 26 units. What is the area of the circle to the nearest hundredth of a square unit
Hitman42 [59]
To find the area of the circle, you will use the formula for finding area of any circle.

The radius is half the diameter.

A = pi x r^2
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3 0
3 years ago
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A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
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