A= 8.55 X 10/-5 and B= 8.55 x 10/6
1) Determine the horizontal force, Fx, exerted by the block on Usain
cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N
2) Determine the Impulse of that force on Usain.
I = F*t = 1597.48N * 0.32s = 511.19 N*s
3) Determine change in momentum of Usain, Δp
Δp = I = 511.19 N*s
4) Find change if velocity
Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s
Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s
Answer: 5.94 m/s
A. No B. No C. Yes I honestly don’t know if that’s 100% right tho
First, change each mixed fraction into improper
2 3/8 = 19/8
1 3/4 = 7/4
The problem will look like: (19/8)/(7/4)
To solve, flip the second fraction, and change the division sign into a multiplication sign.
(19/8)/(7/4) = (19/8) x (4/7)
Multiply across
(19/8) x (4/7) = 76/56
Simplify.
76/56 simplified = 19/14
Change to mixed fraction
19/14 = 14/14 + 5/14 = 1 5/14
1 5/14 is your answer
hope this helps