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3241004551 [841]

3 years ago

8

What postulate can be used to prove the triangles are congruent?

1 answer:

Komok [63]3 years ago

3 0

The HL Postulate

You know that the two hypotenuses are congruent and that the two triangles each contain a shared segment in the middle (so by the reflexive property they are congruent). You have two congruent hypotenuses and two congruent legs, so you can conclude congruency by HL.

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Please help me Im almost done

SSSSS [86.1K]

Answer:

$\mathsf {x = 76}$

Step-by-step explanation:

The given pair of angles lie on a line, hence they are classified as linear angles. They possess the property by which their sum is equal to 180°.

$\textsf {Solving :}$

$\implies \mathsf {x + 17 + 87 = 180}$

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2 years ago

Find the limit of the function by using direct substitution.

serg [7]

Answer:

Option a.

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Step-by-step explanation:

You have the following limit:

$\lim_{x \to \frac{\pi}{2}{(3e)^{xcosx}$

The method of direct substitution consists of substituting the value of $\frac{\pi}{2}$ in the function and simplifying the expression obtained.

We then use this method to solve the limit by doing $x=\frac{\pi}{2}$

Therefore:

$\lim_{x \to \frac{\pi}{2}}{(3e)^{xcosx} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})}$

$cos(\frac{\pi}{2})=0\\$

By definition, any number raised to exponent 0 is equal to 1

So

$\lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}(0)}\\\\$

$\lim_{x\to \frac{\pi}{2}}{(3e)^{0}} = 1$

Finally

$\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1$

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Answer:

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Step-by-step explanation:

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Inessa [10]

10 students will be late.

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