terms is x first then terms in y and constant after the equals
Its C
Answer:
-2
Step-by-step explanation:
Answer:
Incorrect
Step-by-step explanation:
Juanita is incorrect because she shouldn't be using 2 squared.
Answer:
The inverse relation G^(-1) is not a function. Why not? Because the y value y = 3 is paired up with more than one x value (x = 5, x = 2). The inverse relation G^(-1) is the set shown below
{(3,5), (3,2), (4,6)}
All I've done is swap the (x,y) values for each ordered pair to form the inverse relation. As you can see, x = 3 leads to multiple y value outputs which is why this relation is not a function. So in short, the answer is choice C. To have the inverse relation be a function, each value in the original domain must map to exactly one value in the range only. However that doesn't happen as the domain values map to an overlapping y value (y = 3).
