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ololo11 [35]
3 years ago
14

Does someone know how to solve this?​

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

Answer:

multiply the length by the height and the height times 4

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The most recent poll of 50 randomly-selected members of a school club with a total of 80 members showed that 38 are planning to
melisa1 [442]

Answer with Explanation:

Total number of members in School Club = 80 members

Number of member randomly Selected,that is sample size used  (P) = 50 members

Number of members who are planning to vote for Talia = 38 members

Z Score for 95% confidence interval =1.96

it is given that Margin of Error ,E,of the poll using a 95% confidence interval=12%

E=\frac{Z*\sigma}{\sqrt{P}}\\\\ \frac{12}{100}=\frac{1.96 * \sigma}{\sqrt{50}}\\\\ \sigma=4.32890

Standard Deviation=4.3 (approx)

→95% confidence level for students who are planning to vote for Talia as president of the club lie between → 38 + 4.3 = 42.3 to 38 -4.3=33.7.

→So, members which will vote for Talia as president of the club lies between minimum of 33 members and maximum of 42 members.

5 0
3 years ago
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STatiana [176]
The answer is 10,5 i think
5 0
2 years ago
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Simplify sqrt 244x + sqrt 36x - sqrt 25x
Morgarella [4.7K]
First simplify the square roots: 2 \sqrt{61x}+6 \sqrt{x}-5 \sqrt{x}
Then simplify the last two terms: 2 \sqrt{61x}+\sqrt{x}
Since 61 is prime, you can't take a rational root out of it. 
8 0
3 years ago
Hiya !
Aleksandr [31]

Answer:

root 25

Step-by-step explanation:

root 25 is 5, and every other number may not be able to be written as a whole number (please give brainliest)

8 0
2 years ago
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TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?
egoroff_w [7]

Answer:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

Step-by-step explanation:

3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12

Taking square root both sides, we get

\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}

Therefore, the values of b are:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

5 0
3 years ago
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