A vector has a magnitude of 43

Mathematics

1 answer:

posledela3 years ago

5 0

30.8 m

Step-by-step explanation:

Given: $V = 43\:\text{m}$ , $V_y = 30\:\text{m}$

The x-component of vector $\vec{\text{V}}$ is

$V_x = \sqrt{V^2 - V_y^2} = \sqrt{(43)^2 - (30)^2} = 30.8\:\text{m}$

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The exterior angles of an octagon are 42°, 55°, 39°, 20°, 62°, 45°, and 47°. What is the measure of the eighth exterior angle? S

marysya [2.9K]

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Thus, the eighth exterior angle is equal to
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3 years ago

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How to solve this 4x-3(x-2)=21

Natasha_Volkova [10]

We can start by getting rid of parenthesis:

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The question is below thanks

Paha777 [63]

Answer:

FH ~ 10.02

Step-by-step explanation:

1. Approach

One should first find the circumference of the given circle. Then one should find how large the fraction of the circumference one is supposed to find is. Finally, one should multiply the fraction of the circumference one is supposed to find by the total circumference.

2. Circumference of the circle

The formula for circumference is;

$2r$ π

Substitute in the given values;

It is given that the radius is, hence

2 (7) π

14π

3. Find the fraction of the circumference one is supposed to find

It is given that the angles over the measure of the total degrees of angles in a circle are equal to the arc surrounding the angles of the circumference. Essentially;

$\frac{angles}{360}=\frac{arc}{circumference}$