Question

A vector has a magnitude of 43

Answer 1

30.8 m

Step-by-step explanation:

Given: $V = 43\:\text{m}$, $V_y = 30\:\text{m}$

The x-component of vector $\vec{\text{V}}$ is

$V_x = \sqrt{V^2 - V_y^2} = \sqrt{(43)^2 - (30)^2} = 30.8\:\text{m}$