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3 years ago

Multiply. (x−5)(3x+6) Express the answer in standard form.

Mathematics

2 answers:

sergey [27]3 years ago

6 0

Answer:

$3x^{2} -9x-30$

Step-by-step explanation:

(x - 5)(3x + 6)

$3x^{2} +6x-15x-30\\3x^{2} -9x-30$

vodomira [7]3 years ago

5 0

Answer:

3x² - 9x - 30

General Formulas and Concepts:

Algebra I

Expand by FOIL (First Outside Inside Last)
Combining Like Terms

Step-by-step explanation:

Step 1: Define

(x - 5)(3x + 6)

Step 2: Expand

Expand [FOIL]: 3x² + 6x - 15x - 30
Combine like terms: 3x² - 9x - 30

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What si the soulution of 2/3 a - 1/6 = 1/3

11Alexandr11 [23.1K]

Answer:

3/4

Step-by-step explanation:

2/3a-1/6=1/3

2/3a=1/3+1/6

2/3a=3/6

2/3a=1/2

a=1/2X3/2

a=3/4

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3 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form

tino4ka555 [31]

We have the triangle 30° - 60° - 90°.

The lenght of the sides are in proportion: $1:2:\sqrt3\to a:2a:a\sqrt3$

$a=y\\2a=x\\a\sqrt3=5\\\\a\sqrt3=5\qquad\text{multiply both sides by}\ \sqrt3\\\\3a=5\sqrt3\qquad\text{divide both sides by 3}\\\\a=\dfrac{5\sqrt3}{3}\\\\2a=2\cdot\dfrac{5\sqrt3}{3}=\dfrac{10\sqrt3}{3}\\\\Answer:\ x=\dfrac{10\sqrt3}{3},\ y=\dfrac{5\sqrt3}{3}$

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3 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$