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vova2212 [387]
2 years ago
13

Find the measure of a. A. 20 B. 70 C. 80 D. 40

Mathematics
1 answer:
polet [3.4K]2 years ago
8 0
I think it’s 80 :) hope this helps
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Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about the origin, (0,0). y 71 c 3+ 2+ 2 1 2 3 4 5 6 7
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The answer to question 3 is D. 15(4a+3). And the answer to question 4 is A. 90. Have a great day
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Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u
Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

z=\frac{x-\mu}{\sigma}

Plug in the values and solve for 'z'. This gives,

z=\frac{2.33-1.75}{0.22}=2.64

So, the z-score of the distribution is 2.64.

Now, we need the probability P(x\geq 2.33 )=P(z\geq  2.64).

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

P(z\geq  2.64)=1-0.9959=0.0041=0.41\%

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

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3 years ago
The time to complete a standardized exam is approximately normal with a mean of 70 minutes & a standard deviation of 10 minu
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</span>
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3(2x-4)=2(x+4)
6x-12=2x+8
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4x=20
x=20/4
x=5
7 0
3 years ago
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