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zepelin [54]
4 years ago
15

A submarine at a depth of -25 2/3feet descended 5 1/3. How many feet must the submarine rise to reach the surface?

Mathematics
1 answer:
zheka24 [161]4 years ago
7 0

Answer:

it descended 31 Feet b b b b b b b b b bb b b b b b b  b b b b

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Find the area of the trapezoid to the nearest tenth.
erica [24]

Answer:

2.2 metres squared

Step-by-step explanation:

We need to find the area of this trapezoid.

The area of a trapezoid is denoted by:

A=\frac{(b_1+b_2)h}{2}, where b_1 and b_2 are the parallel bases and h is the height

Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.

Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:

2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4

Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:

A=\frac{(b_1+b_2)h}{2}

A=\frac{(0.9+2.3)*1.4}{2}=2.2

The answer is thus 2.2 metres squared.

<em>~ an aesthetics lover</em>

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3 years ago
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vova2212 [387]

Answer:

y = mx + 1/2

Step-by-step explanation:

(x,y)

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+5 is greater that -5 and is also a opposite integer.

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