Answer:
Rounding to nearest hundredths gives us r=0.06.
So r is about 6%.
Step-by-step explanation:
So we are given:
where
.
Divide both sides by 1600:
Simplify:
Take the 6th root of both sides:
![\sqrt[6]{\frac{23}{16}}=1+r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D%3D1%2Br)
Subtract 1 on both sides:
![\sqrt[6]{\frac{23}{16}}-1=r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1%3Dr)
So the exact solution is ![r=\sqrt[6]{\frac{23}{16}}-1](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1)
Most likely we are asked to round to a certain place value.
I'm going to put my value for r into my calculator.
r=0.062350864
Rounding to nearest hundredths gives us r=0.06.
Answer:
AC=14
X=10
Y=1
Hoped this helped!
Step-by-step explanation:
DE is half of BC, therefore x=10. AE and EC have to be the same length, which is 7. SO, y=1 and x is 10.
Answer:
Step-by-step explanation:
I can assist whenever I can.
Answer:
1/6 p -4/5
Step-by-step explanation:
- 2/3p + 1/5 - 1 + 5/6p
When I combine like terms, I put them next to each other.
- 2/3p + 5/6p+ 1/5 - 1
We need to get a common denominator of 6 for the p terms
-2/3 *2/2 p + 5/6 p
-4/6p + 5/6 p
1/6 p
We need to get a common denominator of 5 for the contant terms
1/5 - 1*5/5
1/5-5/5
-4/5
Substituting these in
2/3p + 5/6p+ 1/5 - 1
1/6 p -4/5
Answer:
Hello! The answer to your question will be below.
Step-by-step explanation:
The answer would be clockwise.
So point k was rotated 90 degrees clockwise.....
Review.....
Question:
Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.
THE DIRECTION OF THE ROTATION WAS CLOCKWISE.
Hope this helps! :)
⭐️Have a wonderful day!⭐️
