Inert gases are gases that don't react with other elements. What this means is that they won't combine with other elements, and trigger chemical reactions. I've posted a picture of the Periodic Table. Take a look at the VERY LAST row, all the way on the RIGHT side of the table. That row is made of up NOBLE GASES (He, Ne, Ar, Kr, etc.) Those noble gases are INERT. They are non-reactive.
Answer:
B. ADDITION OF TWO GROUPS ACROSS A DOUBLE BOND
Explanation:
Addition reaction of alkenes involves the conversion of the double bond in alkenes Inyo single bonds by the addition of two groups of atoms or radicals.
During this addition reaction, two substances, an unsaturated compound(e.g. ethane) and an attacking reagent (hydrogen, halogens, hydrogen halides, chlorine and bromine water) combines to form a single new compound without forming any other products. So a saturated product or one in which is an increase in degree of saturation is formed.
The change in the internal energy of the gas is 1.5×10∧3 J.
The internal energy of an ideal gas is directly proportional to the temperature of the gas:
ΔE = 3/2 × n × R × ΔT
ΔT = 320 K - 260 K
ΔT = 60 K; change of the temperature
n = 2.0 mol: amount of a monatomic ideal gas
R = 8.1 J/mol×K;the ideal gas constant
ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K
ΔE = 1500 J
ΔE = 1.5×10∧3 J; the internal energy of the gas
Isobaric process is a type of process in which the pressure of the system stays constant.
More about an isobaric process: brainly.com/question/28106078
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Answer: try to understand coz the question is not valid
Explanation: Explain the relationship between forward and reverse reactions at equilibrium and predict how changing the amount of a reactant or product (creating a stress) will affect that relationship.For example (select one from each underlined section)If the amount of (reactant or product) increases, the rate of the (forward or reverse)reaction will (increase or decrease)to reach a new equilibrium. If the amount of (reactant or product) decreases, the rate of the (forward or reverse)reaction will (increase or decrease)to reach a new equilibrium. Procedure: Access the virtual lab and complete the inquiry experiment
Answer:
q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.
Explanation:
The Specific Heat capacity of Lead is 0.128 
This means, increase in temperature of 1 gm of lead by 
will require 0.128 J of heat.
Formula Used :
q = amount of heat added / removed
m = mass of substance in grams = 85.0 g
c = specific heat of the substance = 0.128
= Change in temperature
= final temperature - Initial temperature
= 10 - 200
= -
put value in formula
q = - 
On calculation,
q = - 2067.2 J
- sign indicates that the heat is released in the process
