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matrenka [14]
3 years ago
12

Is this correct??? Will give Brainlyist

Mathematics
1 answer:
masya89 [10]3 years ago
7 0
It.s not correct, but it’s not hard to learn. All you really have to do is multiply both the numerator and the denominator by each of the numerators that are listed in the problem. If you need help just ask, but I’m not going to give you the problem because you can do it! Just ask if you don’t understand.
You might be interested in
3∣a−b∣ if a=−9 and b=3
yKpoI14uk [10]

Answer:

36 because the absolute value of -9-3 is 12, and then 12 times 3 is 36

8 0
2 years ago
ben used 124.7 pounds of gravel in his front yard 110.7 pounds in his back yard.how many more pounds of gravel does ben use in h
Dovator [93]

Answer:

30.1

Step-by-step explanation:

it is subtraction because it is asking how many more pounds of gravel does Ben use in his front yard than his back yard and his front yard has a bigger number so you subtract.

136.2-106.1= 30.1

6 0
3 years ago
Find X in this question
Andreas93 [3]

Answer:

Step-by-step explanation:

∠1 = 38    {Vertically opposite angles}

∠2 = 39 + 36 = 75

Exterior angle equals the sum of opposite interior angles.

x = ∠1 +∠2        

 = 38 + 75

x = 113

7 0
3 years ago
Is 593÷6 is a little less than 10 a little more than 10 a little less than 100 a little more than 100 explain
DerKrebs [107]
Since 600 ÷ 6 = 100 and 593 is less than 6, 593 ÷ 6 is a little less than 100.

Hope this helps!
4 0
3 years ago
F:[1/2,infinity)—&gt;[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain
dexar [7]

Answer:

f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

\pm \sqrt{y-3/4}=x-1/2

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

\sqrt{y-3/4}=x-1/2

Add 1/2 on both sides:

1/2+\sqrt{y-3/4}=x

The last step is to switch x and y:

1/2+\sqrt{x-3/4}=y

y=1/2+\sqrt{x-3/4}

f^{-1}(x)=1/2+\sqrt{x-3/4}

8 0
3 years ago
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