We can start with the point-slope form of the equation for a line. To meet the given requirements, we can use a point of (5, 0) and a slope of -1. Then the equation in that form is ...

y -0 = -1(x -5)

Simplifying gives the slope-intercept form:

y = -x +5 . . . . . . . use the distributive property to eliminate parentheses

Adding x to both sides gives the standard form:

x + y = 5

<em>Explanation</em>

We know the line has the required intercept and slope because we chose those values to put into the point-slope form. Conversion from one form to another made use of the rules of equality, the additive identity element (y-0=y), and the distributive property.

8 0

2 years ago

How do you graph, identify the domain, range, and asymptotes for y=-2csc2x-1?

faltersainse [42]

The domain is all real numbers except kπ, where k is an integer.
The range is (-∞, -1] ∪ [1, ∞)
Vertical asymtote is kπ, where k is an integer.

4 0

3 years ago