Plot the image abc under a reflection

The New Mexico Division of Fish and Wildlife keeps track of the silvery minnow population in the Rio Grande River. They tagged 5

sattari [20]

Answer:

279 silvery minnow

Step-by-step explanation:

Number of Silvery Minnows initially tagged = 54

Number of minnows captured = 62

Number of tagged minnows in captured ones = 12

Remember that in the very beginning there were no tagged minnows. 54 minnows were captured, tagged and released. This means, there are total 54 tagged minnows in the entire population. Lets say there are x number of minnows in total.

So, in x minnows, 54 are tagged ones.

When 62 minnows are captured, only 12 are tagged ones and remaining are un-tagged. Since, the minnows were randomly captured, we can develop a proportion from this case to estimate the total population of minnows in the Rio Grande River.

Ratio of tagged minnows to total population must be equal to the ratio of captured tagged minnows in total captured minnows.

i.e.

$54 : x = 12 : 62\\\\ \frac{54}{x} = \frac{12}{62}\\\\ 62(54)=12x\\ \\ x = 279$

This means, there were 279 silvery minnows in the Rio Grande River.

3 0

3 years ago

What is the inequality of 2/3 and 4/6?

zhannawk [14.2K]

2/3 and 4/6 are equal.

3 0

3 years ago

REALLY NEED HELP WITH THIS!!!

koban [17]

Answer:

9

Step-by-step explanation:

Solve the equation

Area =1/2(heightxbase)

27=1/2(Xx6)

54=6x

9 =x

4 0

3 years ago

5*10^5 is how many times bigger that 1*10^5

weqwewe [10]

Answer:

5

Step-by-step explanation:

5*10^5=500000 and 1*10^5=100000

6 0

3 years ago

A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The

brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

$\overline{X} = \frac{X_1+X_2+...+X_n}{n}$

If $X_1, ..., X_n$ are indentically distributed and independent, like in the situation of the problem, then the variance of $X_1 + .... + X_n$ will be the sum of the variances, in other words, it will be n times the variance of $X_1$ .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus $\overkine{X} = \frac{V(X_1)}{n}$ and as a result, the standard deviation of $\overline{X}$ is the standard deviation of $X_1$ divided by $\sqrt{n}$ .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

Restaurants: We have boxes with 9 salmon each, so it will be $\frac{2}{\sqrt{9}} = \frac{2}{3}$
Grocery stores: Each carton has 49 salmon, thus the standard deviation is $\frac{2}{\sqrt{49}} = \frac{2}{7}$
Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is $\frac{2}{\sqrt{64}} = \frac{1}{4}$

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0

3 years ago