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3 years ago

11

Which graph best represents the equation 5x + 2y = 7?

2 answers:

vitfil [10]3 years ago

7 0

Answer:

D

Step-by-step explanation:

Bond [772]3 years ago

5 0

Answer:

D

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PLEASE HELP WILL GIVE BRANLIEST IF CORRECT

nevsk [136]

Answer:

1,500,000,000

Step-by-step explanation:

6 0

3 years ago

What is the slope of the line 6x + y = 24?

ValentinkaMS [17]

Answer:

-6

Step-by-step explanation:

You need to get it in Point-Slope form, or

y = mx + b

Isolate y by subtracting 6x

You are left with:

y = -6x + 24

M is the slope, so in this case, it is -6

5 0

3 years ago

Read 2 more answers

How do you do this? Please help

PtichkaEL [24]

Answer:

$PO=86.2\\ OM=23.8\\$

Step-by-step explanation:

To preface, your figure is going to be a line segment, with $O$ as your midpoint, in between points $P$ & $M.$

With that being said:

$PO+OM=PM$

Identify your values:

$PO=7y+12\\OM=3y-8\\PM=110$

Substitute the values into the first equation:

$7y+12+3y-8=110$

Combine like terms:

$10y+4=110$

Subtract $4$ from both sides of the equation:

$10y=106$

Divide by the coefficient of $y$ , which is $10$ :

$y=10.6$

Substitute $10.6$ for $y$ in segments $PO$ & $OM$ :

$PO=7(10.6)+12$

$OM=3(10.6)-8$

$PO=74.2+12$

$OM=31.8-8$

Solve:

$PO=86.2$

$OM=23.8$

Check your answers by substituting:

$PO+OM=PM$

$86.2+23.8=110$

8 0

4 years ago

9. (4,10) and (-2,-5)<br>Slope:

marshall27 [118]

Answer:

-7/2

Step-by-step explanation:

y2-y1 / x2-x1

-5-10 / -2-4

-15 / -6

-7 / -2

= -7/2

4 0

3 years ago

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

1 year ago