All categories

3 years ago

Is this equation linear?

Mathematics

1 answer:

Finger [1]3 years ago

8 0

yes it is a linear factor, my sister told me the answser

(not sure):

You might be interested in

What is the value of -2x²y³ when ×=2 and y=4?

Reptile [31]

Answer:

1024

Step-by-step explanation:

Given :-

x = 2
y = 4

Value of -2x²y³

2x³ y³
2 * (2)³ * (4)³
2 * 8 * 64
1024

6 0

3 years ago

Read 2 more answers

Why do economists pay a great deal of attention to the baby boom generation?

MatroZZZ [7]

Answer:

I hope this answer is correct

Step-by-step explanation:

This generation represents a large portion of the current population. As they age, they will cause changes to the economy. The population has grown considerably, but the rate has slowly declined.

5 0

4 years ago

Cab rides from Brooklyn to Manhattan are usually around $20. Today it cost me $24. Cab rides from Brooklyn to Boston are usually

AysviL [449]

Answer:

the answer is c i guess

5 0

3 years ago

What is the derivative of x to the minus 5 power

Rudiy27

Using implicit differentiation:

$y={ x }^{ -5 }\\ \\ y=\frac { 1 }{ { x }^{ 5 } } \\ \\ { x }^{ 5 }\cdot y=\frac { 1 }{ { x }^{ 5 } } \cdot { x }^{ 5 }$

$\\ \\ { x }^{ 5 }\cdot y=1\\ \\ { x }^{ 5 }\frac { dy }{ dx } +5{ x }^{ 4 }\cdot y=0$

$\\ \\ { x }^{ 5 }\frac { dy }{ dx } =-5{ x }^{ 4 }\cdot y\\ \\ { x }^{ 5 }\frac { dy }{ dx } =-5{ x }^{ 4 }\cdot \frac { 1 }{ { x }^{ 5 } }$

$\\ \\ \frac { 1 }{ { x }^{ 5 } } \cdot { x }^{ 5 }\frac { dy }{ dx } =-5{ x }^{ 4 }\cdot \frac { 1 }{ { x }^{ 5 } } \cdot \frac { 1 }{ { x }^{ 5 } }$

$\\ \\ \frac { dy }{ dx } =-\frac { 5{ x }^{ 4 } }{ { x }^{ 10 } } \\ \\ =-\frac { 5 }{ { x }^{ 6 } }$

3 0

4 years ago

Read 2 more answers

Prove that a line parallel to one side of a triangle divides the other two sides proportionally. Be sure to create and name the

ryzh [129]

Answer:

in steps

Step-by-step explanation:

DE // BC

m∠ADE = m∠ABC and m∠AED = m∠ACB

∴ ΔADE similar to ΔABC

AB/AD = AC/AE

(AD + DB) / AD = (AE + EC) / AE

AD/AD + DB/AD = AE/AE + EC/AE

1 + DB/AD = 1 + EC/AE

DB/AD = EC/AE (AD/DB = AE/EC)

7 0

3 years ago