Solve the equation -2/3d-1/4d=-22

An Eurasian lynx travled 46 miles. It took the

Eddi Din [679]

Answer:

A Eurasian lynx covered 1.07 miles per day.

Step-by-step explanation:

The distance traveled by a Eurasian lynx = 46 miles

The days to cover the 46 miles distance = 43 days

Divide the total distance miles by the total number of days to determine the miles per day.

Thus,

Miles per day = Tota distance / Totdal days

= 46 / 43

= 1.07 miles per day

Thus, An Eurasian lynx covered 1.07 miles per day.

6 0

3 years ago

Please help (10 points)

Norma-Jean [14]

Answer:

-3x/4 - 5/6

Step-by-step explanation:

Thats the answer trust me

4 0

3 years ago

-18 subtracted from - 7

castortr0y [4]

The answer is 11 my friend :)

5 0

3 years ago

Read 2 more answers

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

<u>Algebra I</u>

Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$ <u />

<u />

<u>Step 2: Integrate Pt. 1</u>

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

<u>Step 4: Integrate Pt. 2</u>

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0

3 years ago

Probability, help, please <br><br>

Butoxors [25]

Problem 1

<h3>Answer: Choice A) 1/3</h3>

-------------------

Explanation:

The notation "P(tune-ups | AC repair)" is the same as saying "P(tune-ups given AC repair)".

The "given" means we only focus on the "AC repair" circle.

Add up the numbers in that circle to get: 1+3+2+0 = 6

There are 6 ASE certified mechanics that can do AC repair.

Of those 6 people, only 2+0 = 2 can do engine tune-ups. Note I added the values in the "AC repair" and "tune-ups" overlapped region.

Therefore, we get the probability 2/6 = 1/3

==========================================================

Problem 2

<h3>Answer: B) 2/3</h3>

-------------------

Explanation:

First, we'll add the numbers found in either the "brakes" or "tune-ups" circles.

4+1+2+2+3+0 = 12

There are 12 mechanics that can handle brakes or tune-ups or both.

Now add up all of the numbers shown regardless of their location. We have 4+1+3+2+2+0+3+3 = 18 mechanics total.

So,

m = number who can do brakes or tune-ups or both

m = 12

n = number of mechanics total

n = 18

And,

P(brakes or tune-ups) = m/n

P(brakes or tune-ups) = 12/18

P(brakes or tune-ups) = (6*2)/(6*3)

P(brakes or tune-ups) = 2/3

5 0

3 years ago