Answer:
The perimeter of the rectangle is 10.5p + 10.7q - 3.8r
Step-by-step explanation:
The perimeter of the triangle is calculated by adding the values of the three sides.
In this case, the values of the individual sides are expressed algebraically.
We can still add them, however, taking into consideration like terms.
Perimenter of triangle = (4.1p+4.4q) + (6.4p-5.1r) + (1.3r+6.3q)
Perimeter = 4.1p + 6.4p + 4.4q + 6.3q -5.1r + 1.3r
Now we have grouped them, we can add the different groups separately
Perimeter = 10.5p + 10.7q - 3.8r
Therefore, the perimeter of the rectangle is 10.5p + 10.7q - 3.8r
Title:
<h2>See the explanation.</h2>
Step-by-step explanation:
It is given that, if 100 persons book their seats, then only 88 passengers come.
The probability of 1 passenger to come is = 0.88.
There will not be enough seats only when, 331 or more than 331 passengers will come.
The probability of 1 passenger will not come is (1 - 0.88)= 0.12.
Out of 354 passengers the probability that n passengers will come is .
The required probability is ∑, where .
Answer:
Third option is the right choice.
Step-by-step explanation:
Manipulate the right hand side.
Best Regards!
Since the ratio is 5:4, they had to multiply 5x11 to get the 55. Now multiply the 4x11 to get 44. When you add the 55 and 44 that's 99 which only leaves 1 for the independent.
Answer:
A Mudslinger tire weighs 20.71 pounds and a Roadripper tire weighs 19.52 pounds
Step-by-step explanation:
Let the weight of a Mudslinger tire=m
Let the weight of a Roadripper tire=r
4 Mudslinger tires and 6 Roadripper tires weigh 200 pounds
4m+6r=200.....(i)
7 Mudslinger tires and 2 Roadripper tires weigh 184 pounds
7m+2r=184....(ii)
To find the values of m and r, we solve the two derived equations simultaneously.
4m+6r=200.....(i)
7m+2r=184....(ii)
Multiply (ii) by 3 to get (iii)
21m+6r=552....(iii)
4m+6r=200.....(i)
SUbtract (i) from (iii)
17m=352
m=352/17=20.71 pounds
Substitute m=20.71 in (i)
4(20.71)+6r=200
6r=200-82.84=117.16
r=117.16/6=19.52 pounds