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Snezhnost [94]
2 years ago
8

HELP!? ✋

Mathematics
1 answer:
Korolek [52]2 years ago
3 0
All of them are strategies for preventing cancer
You might be interested in
wanting some extra help with factoring while knowing what method it would be like gcf or grouping etc
Ksju [112]

d) You have a <u>difference of squares</u>:

49y² - 9 = (7y)² - 3²

Recall the identity,

a² - b² = (a - b) (a + b)

So,

49y² - 9 = (7y - 3) (7y + 3)

e) Pull out the common factor 3 from each term:

3x² - 3x - 90 = 3 (x² - x - 30)

Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so

3x² - 3x - 90 = 3 (x + 5) (x - 6)

f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so

x² - 13x + 42 = (x - 7) (x - 6)

8 0
1 year ago
Read 2 more answers
A rectangular one story house covers an area of 3,700 square feet. The ceilings are 8 feet high. What is the volume of the inter
notsponge [240]

Answer:

43100 cubic feet

Step-by-step explanation:

Floor 1: 3700 * 8 = 29600

Floor 2: 50 * 30 * 9 = 13600

Total = 29600+13600=43100

8 0
3 years ago
Evaluate:
EleoNora [17]

Answer:

1

Step-by-step explanation:

all you do is multiple then devide

8 0
3 years ago
A survey found that women's heights are normally distributed with mean 62.7 in, and standard deviation 2.8 in. The survey also f
Viefleur [7K]

Using the normal distribution, we have that:

The percentage of men who meet the height requirement is 3.06%. This suggests that the majority of employees at the park are females.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation of men's heights are given as follows:

\mu = 69.3, \sigma = 3.9.

The proportion of men who meet the height requirement is is the <u>p-value of Z when X = 62 subtracted by the p-value of Z when X = 55</u>, hence:

X = 62:

Z = \frac{X - \mu}{\sigma}

Z = \frac{62 - 69.3}{3.9}

Z = -1.87

Z = -1.87 has a p-value of 0.0307.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 69.3}{3.9}

Z = -3.67

Z = -3.67 has a p-value of 0.0001.

0.0307 - 0.0001 = 0.0306 = 3.06%.

The percentage of men who meet the height requirement is 3.06%. This suggests that the majority of employees at the park are females.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
1 year ago
The number of bacteria in a petri dish is 524 and growing at a rate of 7% every month.
kicyunya [14]
This is an exponential growth problem.
y = 524(1.07)^7
y = 841 bacteria after 7 months
7 0
3 years ago
Read 2 more answers
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